Proof: Consider a line through the right angle and perpendicular to the hypothenuse. This line splits the hypothenuse into two pieces of length `d` and `c-d`. By similar triangles, `\frac{a}{c}=\frac{d}{a}` and `\frac{b}{c}=\frac{c-d}{b}`.
Therefore `a^2=c*d` and `b^2=c*(c-d)`, hence `a^2+b^2=c*d+c*(c-d)=c*d+c^2-c*d=c^2`.
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width=600;
height=300;
initPicture(-6,6,-1,5);
A = [5,0];
B = [-5,0];
O = [0,0];
t = -2;
update2();
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Move the pointer over the picture to see different right-angled triangles.
The proof given above applies to all of them.
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ASCIIsvg
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Chapman University (jipsen@chapman.edu) LaTeXMathML has been developed by Douglas Woodall (and exteded by Jeff Knisley), based on ASCIIMathML The version of ASCIIMathML used here, is a modified and extended version, developed by Dr.ir. S.A. Miedema Other sources: An ASCIIsvg manual by Robert Fant. An ASCIIsvg manual by Peter Jipsen. An ASCIIMathML manual by James Gray.
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